[Olsr-dev] getting the etx value to a destination

sebastian sauer (spam-protected)
Wed Jul 15 16:39:57 CEST 2009


Hi,

Wed 15 Jul 2009 16:30, ZioPRoTo (Saverio Proto) wrote:
> > 13:42:38.975 DEBUG(plugins) src/obamp.c 421: ROUTING TO node
                                                 ^^^^^^^^^^^^^^^
prob. means Path ETX

> > 172.16.100.1 costs 131072
> > 13:42:38.983 DEBUG(plugins) src/obamp.c 421: ROUTING TO node
> > 172.16.100.4 costs 65536
> 
> I just noticed that I get this numbers
> 
> 65536 = 1x2^16
> On 1 hop with no packet loss
> 
> 131072 = 2 x 2^16
> On two hops with no packet loss
> 
> So to get the ETX I divide this value by 2^16 ??
let's see what Hennig says, but for a Path ETX it makes sense.

Path ETX = sum over all ETX along the path




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